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A125714
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Alfred Moessner's factorial triangle.
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17
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1, 2, 3, 6, 11, 6, 24, 50, 35, 10, 120, 274, 225, 85, 15, 720, 1764, 1624, 735, 175, 21, 5040, 13068, 13132, 6769, 1960, 322, 28, 40320, 109584, 118124, 67284, 22449, 4536, 546, 36, 362880, 1026576, 1172700, 723680, 269325, 63273, 9450, 870, 45, 3628800
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OFFSET
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1,2
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COMMENTS
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Successive numbers arising from the Moessner construction of the factorial numbers. - N. J. A. Sloane, Jul 27 2021
Row sums of the triangle = 1, 5, 23, 119, 719, ...(matching the terms 0, 0, 1, 5, 23, 119, 719, ...; of A033312).
The name of the triangle derives from the fact that A125714(A000124(n)) = A000142(n) for n > 0. Moessner's method uses only additions to compute the factorial n!. - Peter Luschny, Jan 27 2009
If n = (m^2+m+2)/2 then a(n) = (m+1)!. For example, taking m = 3, n = 7, and indeed a(7) = 4! = 24. - N. J. A. Sloane, Jul 27 2021
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REFERENCES
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J. H. Conway and R. K. Guy, "The Book of Numbers", Springer-Verlag, 1996. Sequence can be seen by reading the successive circled numbers in the "factorial" section on page 64 (based on the work of Alfred Moessner).
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LINKS
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FORMULA
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Starting with the natural numbers, circle each triangular number. Underneath, take partial sums of the uncircled terms and circle the terms in this row which are offset one place to the left of the circled 1, 3, 6, 10, ... in the first row. Repeat with analogous operations in succeeding rows. The circled terms in the infinite set become the triangle.
Given n, let j = A003056(n-1)+1 and set t = j*(j+1)/2. Then, for 0 <= i < t, if n == -i (mod t), a(n) = abs(Stirling_1(j+1,j-i)). - N. J. A. Sloane, Jul 27 2021
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EXAMPLE
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An "x" prefaced before each term will indicate the term following the x being circled.
x1 2 x3 4 5 x6 7 8 9 x10 11 12 13 14 x15 ...
__x2 6 x11 18 26 x35 46 58 71 x85 ...
_____________x6 24 x50 96 154 x225 ...
_________________________x24 120 x274 ...
___________________________________________x120 ...
...
i.e., circle the triangular terms in row 1. In row 2, take partial sums of the uncircled terms and circle the terms offset one place to the left of the triangular terms in row 1. Continue in subsequent rows with analogous operations. The triangle consists of the infinite set of terms prefaced with the x (circled on page 64 of "The Book of Numbers").
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MAPLE
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a := proc(n) local s, m, k, i; s := array(0..n); s[0] := 1;
for m from 1 to n do s[m] := 0; for k from m by - 1 to 1 do
for i from 1 to k do s[i] := s[i] + s[i - 1] od; lprint(s[k]);
if k = n then return(s[n]) fi od; lprint("-") od end: # Peter Luschny, Jan 27 2009
with(combinat);
s:=stirling1;
A003056 := proc(n) floor((sqrt(1+8*n)-1)/2) ; end proc:
g:=proc(n) local i, j, t; global T, A003056;
t:=T(j);
for i from 0 to t-1 do
if ((n+i) mod t) = 0 then return(abs(s(j+1, j-i))); fi;
od;
end;
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MATHEMATICA
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n = 10; A125714 = Reap[ ClearAll[s]; s[0] = 1; For[m = 1, m <= n, m++, s[m] = 0; For[k = m, k >= 1, k--, For[i = 1, i <= k, i++, s[i] = s[i] + s[i-1]]; Sow[s[k]]; If[k == n, Print[n, "! = ", s[n]]; Break[]]]]][[2, 1]] (* Jean-François Alcover, Jun 29 2012, after Peter Luschny *)
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PROG
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(PARI) T(n, k)={ my( s=vector(n)); for( m=1, n, forstep( j=m, 1, -1, s[1]++; for( i=2, j, s[i] += s[i-1]));
k<0 && print(vecextract(s, Str(m"..1"))));
if( k>0, s[n+1-k], vecextract(s, "-1..1"))} /* returns T[n, k], or the whole n-th row if k is not given, prints row 1...n of the triangle if k<0 */ \\ M. F. Hasler, Dec 03 2010
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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