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A119561
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Define F(n) = 2^(2^n)+1 = the n-th Fermat number, M(n) = 2^n-1 = the n-th Mersenne number. Then a(n) = F(n)+M(n)+1=2^(2^n)+1+2^n-1+1 = 2^(2^n)+2^n+1 = F(n)+2^n.
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1
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4, 7, 21, 265, 65553, 4294967329, 18446744073709551681, 340282366920938463463374607431768211585, 115792089237316195423570985008687907853269984665640564039457584007913129640193
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OFFSET
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0,1
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LINKS
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EXAMPLE
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F(1) = 2^(2^1)+1 = 5
M(1) = 2^1-1 = 1
F(1)+M(2)+1 = 7
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MATHEMATICA
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PROG
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(PARI) fm(n) = for(x=0, n, y=2^(2^x)+2^x+1; print1(y", "))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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