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A115593
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Number of forests of rooted trees with total weight n, where a node at height k has weight 2^k (with root considered to be at height 0).
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11
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1, 1, 1, 2, 2, 3, 4, 6, 7, 10, 13, 17, 22, 29, 38, 50, 64, 82, 107, 136, 175, 224, 288, 363, 465, 587, 748, 942, 1196, 1503, 1902, 2385, 3004, 3765, 4729, 5911, 7406, 9246, 11549, 14395, 17941, 22326, 27767, 34501, 42821, 53134, 65828, 81546, 100871, 124783
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OFFSET
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0,4
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COMMENTS
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The sequence b(2n)=0, b(2n+1)=a(n) is the number of trees of weight n.
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LINKS
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FORMULA
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Euler transform of b(n), where b(2n+1) = a(n) and b(2n) = 0.
G.f. satisfies: A(x) = exp( Sum_{n>=1} A(x^(2*n)) * x^n/n ).
G.f. satisfies: A(x)*A(-x) = A(x^2). (End)
Let b(n) = a(n-1) for n>=1, then sum(n>=1, b(n)*x^n ) = x / prod(n>=1, (1-x^(2*n-1))^b(n) ); compare to A000081, A004111, and A073075. - Joerg Arndt, Mar 04 2015
a(0) = 1; a(n) = (1/n) * Sum_{k=1..n} ( Sum_{d|k and d is odd} d * a(floor(d/2)) ) * a(n-k). - Seiichi Manyama, May 31 2023
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EXAMPLE
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a(3) = 2; one forest with 3 single-node trees and one with a single two-node tree (root node has weight 1, other node has weight 2).
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MAPLE
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with(numtheory):
b:= proc(n) local r; `if`(irem(n, 2, 'r')=0, 0, a(r)) end:
a:= proc(n) option remember; `if`(n=0, 1,
add(add(d*b(d), d=divisors(j))*a(n-j), j=1..n)/n)
end:
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MATHEMATICA
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b[n_] := b[n] = If[{q, r} = QuotientRemainder[n, 2]; r == 0, 0, a[q]]; a[n_] := a[n] = If[n == 0, 1, Sum[Sum[d*b[d], {d, Divisors[j]}]*a[n-j], {j, 1, n}]/n]; Table[a[n], {n, 0, 50}] (* Jean-François Alcover, Mar 23 2015, after Alois P. Heinz *)
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PROG
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(PARI) {a(n)=my(A=1+x); for(i=1, n, A=exp(sum(m=1, n, subst(A, x, x^(2*m)+x*O(x^n))*x^m/m))); polcoeff(A, n)} /* Paul D. Hanna */
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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