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A113415 Expansion of Sum_{k>0} x^k/(1-x^(2k))^2. 21

%I #28 Dec 09 2021 01:24:29

%S 1,1,3,1,4,3,5,1,8,4,7,3,8,5,14,1,10,8,11,4,18,7,13,3,17,8,22,5,16,14,

%T 17,1,26,10,26,8,20,11,30,4,22,18,23,7,42,13,25,3,30,17,38,8,28,22,38,

%U 5,42,16,31,14,32,17,55,1,44,26,35,10,50,26,37,8,38,20,65,11,50,30,41

%N Expansion of Sum_{k>0} x^k/(1-x^(2k))^2.

%C Arithmetic mean between the number of odd divisors (A001227) and their sum (A000593). This fact was essentially found by the algorithmic search of _Jon Maiga_'s Sequence Machine, and is easily seen to be correct when compared to the PARI-program given by the original author. - _Antti Karttunen_, Dec 07 2021

%H Antti Karttunen, <a href="/A113415/b113415.txt">Table of n, a(n) for n = 1..20000</a>

%H Jon Maiga, <a href="http://sequencedb.net/s/A113415">Computer-generated formulas for A113415</a>, Sequence Machine.

%F G.f.: Sum_{k>0} x^k/(1-x^(2k))^2 = Sum_{k>0} k x^(2k-1)/(1-x^(2k-1)).

%F a(n) = (1/2) * Sum_{d|n} (d+1)*(d mod 2). - _Wesley Ivan Hurt_, Nov 25 2021 [From PARI prog]

%F From _Antti Karttunen_, Dec 07 2021: (Start)

%F All these formulas, except the last, were found by the Sequence Machine in some form or another:

%F a(n) = (1/2) * (A000593(n)+A001227(n)).

%F a(n) = A069734(A000265(n)). [See either Rutherford's or Luschny's formula in A069734]

%F a(n) = A349371(n) / A001511(n).

%F a(n) = A349371(A000265(n)) = A336840(A064989(n)).

%F a(n) = a(2*n) = a(A000265(n)) = A349916(4*n).

%F (End)

%t Array[DivisorSum[#, If[OddQ[#], (# + 1)/2, 0] &] &, 79] (* _Michael De Vlieger_, Dec 08 2021 *)

%o (PARI) a(n)=if(n<1, 0, sumdiv(n, d, if(d%2, (d+1)/2)))

%Y Cf. A000265, A000593, A001227, A001511, A003602, A048673, A064989, A069734, A336840, A349371, A349915 (Dirichlet inverse).

%Y Quadrisection of A349916.

%K nonn

%O 1,3

%A _Michael Somos_, Oct 29 2005

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