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A110044
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a(0) = 11, a(1) = 23; for n > 1, a(n) = |a(n-1) - a(n-2)|.
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2
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11, 23, 12, 11, 1, 10, 9, 1, 8, 7, 1, 6, 5, 1, 4, 3, 1, 2, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1
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OFFSET
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0,1
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COMMENTS
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Since a(18)=a(19)=1, starting from here the sequence is periodic with period 3: 1,1,0,1,1,0,1,1,0,... - Emeric Deutsch, Jul 13 2005
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LINKS
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FORMULA
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a(n) = 2/3 + 1/3*cos(2*Pi*n/3) + 1/3*3^(1/2)*sin(2*Pi*n/3) for n >= 19. - Richard Choulet, Dec 12 2008
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MAPLE
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a[0]:=11: a[1]:=23: for n from 2 to 120 do a[n]:=abs(a[n-1]-a[n-2]) od: seq(a[n], n=0..120); # Emeric Deutsch, Jul 13 2005
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MATHEMATICA
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Join[{11, 23, 12, 11, 1, 10, 9, 1, 8, 7, 1, 6, 5, 1, 4, 3, 1, 2}, LinearRecurrence[{0, 0, 1}, {1, 1, 0}, 85]] (* Ray Chandler, Aug 25 2015 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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