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A107981
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Triangle read by rows: T(n,k) = (k+1)(k+2)(n+2)(n+3)(6n^2 - 8n*k + 18n + 3k^2 - 11k + 12)/144 for 0<=k<=n.
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0
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1, 6, 10, 20, 40, 50, 50, 110, 155, 175, 105, 245, 371, 455, 490, 196, 476, 756, 980, 1120, 1176, 336, 840, 1380, 1860, 2220, 2436, 2520, 540, 1380, 2325, 3225, 3975, 4515, 4830, 4950, 825, 2145, 3685, 5225, 6600, 7700, 8470, 8910, 9075, 1210, 3190
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OFFSET
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0,2
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COMMENTS
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Kekulé numbers for certain benzenoids. Column 0 yields A002415. Main diagonal yields A006542.
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REFERENCES
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S. J. Cyvin and I. Gutman, Kekulé structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (p. 237, K{F(n,3,l)}).
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LINKS
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EXAMPLE
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Triangle begins:
1;
6,10;
20,40,50;
50,110,155,175;
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MAPLE
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T:=proc(n, k) if k<=n then 1/144*(k+1)*(k+2)*(n+2)*(n+3)*(6*n^2-8*n*k+18*n+3*k^2-11*k+12) else 0 fi end: for n from 0 to 9 do seq(T(n, k), k=0..n) od; # yields sequence in triangular form
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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