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A107428
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Number of gap-free compositions of n.
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18
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1, 2, 4, 6, 11, 21, 39, 71, 141, 276, 542, 1070, 2110, 4189, 8351, 16618, 33134, 66129, 131937, 263483, 526453, 1051984, 2102582, 4203177, 8403116, 16800894, 33593742, 67174863, 134328816, 268624026, 537192064, 1074288649, 2148414285, 4296543181, 8592585289
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OFFSET
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1,2
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COMMENTS
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A gap-free composition contains all the parts between its smallest and largest part. a(5)=11 because we have: 5, 3+2, 2+3, 2+2+1, 2+1+2, 1+2+2, 2+1+1+1, 1+2+1+1, 1+1+2+1, 1+1+1+2, 1+1+1+1+1. - Geoffrey Critzer, Apr 13 2014
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LINKS
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FORMULA
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EXAMPLE
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The a(0) = 1 through a(5) = 11 gap-free compositions:
() (1) (2) (3) (4) (5)
(11) (12) (22) (23)
(21) (112) (32)
(111) (121) (122)
(211) (212)
(1111) (221)
(1112)
(1121)
(1211)
(2111)
(11111)
(End)
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MAPLE
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b:= proc(n, i, t) option remember; `if`(n=0, t!,
`if`(i<1 or n<i, 0, add(b(n-i*j, i-1, t+j)/j!, j=1..n/i)))
end:
a:= n-> add(b(n, i, 0), i=1..n):
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MATHEMATICA
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Table[Length[Select[Level[Map[Permutations, IntegerPartitions[n]], {2}], Length[Union[#]]==Max[#]-Min[#]+1&]], {n, 1, 20}] (* Geoffrey Critzer, Apr 13 2014 *)
b[n_, i_, t_] := b[n, i, t] = If[n == 0, t!, If[i < 1 || n < i, 0, Sum[b[n - i*j, i - 1, t + j]/j!, {j, 1, n/i}]]]; a[n_] := Sum[b[n, i, 0], {i, 1, n}]; Table[a[n], {n, 1, 40}] (* Jean-François Alcover, Aug 30 2016, after Alois P. Heinz *)
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CROSSREFS
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These compositions are ranked by A356841.
A356233 counts factorizations into gapless numbers.
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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