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A106038
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Triangle Loop von Koch substitution: characteristic polynomial:x^3-6x^2+8*x.
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0
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1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 1, 2, 3, 1, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 3
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OFFSET
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0,2
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COMMENTS
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To get the fractal: bb = aa /. 1 -> {1, 0} /. 2 -> {-1, N[Sqrt[3]]}/2 /. 3 -> {-1, -N[Sqrt[3]]}/2; ListPlot[FoldList[Plus, {0, 0}, bb], PlotJoined -> True, PlotRange -> All, Axes -> False];
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LINKS
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FORMULA
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1->{1, 2, 3, 1}, 2->{2, 1, 1, 2}, 3->{3, 1, 1, 3}
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MATHEMATICA
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s[1] = {1, 2, 3, 1}; s[2] = {2, 1, 1, 2}; s[3] = {3, 1, 1, 3};; t[a_] := Flatten[s /@ a]; p[0] = {1}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]] aa = p[4]
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CROSSREFS
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KEYWORD
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nonn,uned
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AUTHOR
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STATUS
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approved
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