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%I #17 Jun 03 2013 03:35:42
%S 2,3,4,5,6,7,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,
%T 28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,
%U 51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74
%N Numbers n such that n^3 can be partitioned into n primes such that n-1 are consecutive primes and the remaining prime is larger than the sum of the n-1 consecutive primes.
%C Indices of nonzero terms in A102706.
%C It appears that this sequence contains all numbers except 1 and 8 - is there a proof?
%e 3 is a member since 3^3 = 27 = 3+5+19, where 3 and 5 are consecutive and 19 > 3+5.
%Y Cf. A102706.
%K easy,nonn
%O 1,1
%A _Giovanni Teofilatto_, Feb 21 2005
%E Edited by _Ray Chandler_ Feb 25 2005
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