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A097990
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A puzzle: reverse digits of n^2 + 10.
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1
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10, 11, 41, 91, 62, 53, 64, 95, 47, 19, 11, 131, 451, 971, 602, 532, 662, 992, 433, 173, 14, 154, 494, 935, 685, 536, 686, 937, 497, 158, 19, 179, 4301, 9901, 6611, 5321, 6031, 9731, 4541, 1351, 161, 1961, 4771, 9581, 6491, 5302, 6212, 9122, 4132, 1142, 152
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OFFSET
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0,1
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COMMENTS
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The first term should really be 1 (cf. A097991, which gives a better version).
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LINKS
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MATHEMATICA
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Do[Print[FromDigits[Reverse[IntegerDigits[n^2 + 10]]]], {n, 0, 50}] (Poff)
Join[{10}, IntegerReverse[Range[50]^2+10]] (* Harvey P. Dale, Feb 27 2024 *)
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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N. J. A. Sloane, following a suggestion of Jacek Kolodziejczyk (zwi(AT)infogenia.pl), Sep 07 2004
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EXTENSIONS
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More terms from Tracy Poff (tracy.poff(AT)gmail.com), Apr 15 2005
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STATUS
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approved
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