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A096295
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a(1) = 2, a(n) = a(n-1) + 3*(a(n-1)-floor(a(n-1)^(1/3))^3).
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0
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2, 5, 17, 44, 95, 188, 377, 479, 887, 1361, 1451, 1811, 2060, 3056, 3992, 5843, 5876, 6008, 6536, 8648, 10592, 14585, 16868, 20597, 23339, 27500, 29000, 35000, 41696, 48872, 55520, 57464, 65240, 68960, 69077, 69545, 71417, 78905, 93356, 100049
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OFFSET
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1,1
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COMMENTS
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A cubic version of the Weintraub recursion.
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LINKS
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MATHEMATICA
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digits=200
a[n_Integer?Positive] := a[n] = a[n-1] + 3*(a[n-1] - Floor[a[n-1]^(1/3)]^3)
a[1] = 2
a0=Table[a[n], {n, 1, digits}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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