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A093098
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"Power into digits": start with a(1)=2, a(2)=3; repeatedly adjoin digits of a(n-2)^a(n-1).
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1
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2, 3, 8, 6, 5, 6, 1, 2, 6, 2, 1, 4, 4, 7, 7, 7, 6, 1, 5, 6, 2, 5, 6, 1, 6, 4, 3, 6, 2, 1, 2, 5, 6, 1, 6, 3, 8, 4, 8, 2, 3, 5, 4, 3, 8, 2, 3, 5, 4, 3, 1, 1, 7, 6, 4, 9, 6, 1, 1, 5, 6, 2, 5, 3, 6, 3, 2, 1, 5, 6, 2, 5, 6, 1, 1, 2, 9, 6, 6, 4, 7, 2, 9, 3, 6, 2, 1, 3, 2, 1, 5, 6, 2, 5, 6, 1, 2, 1, 6, 6, 5, 6, 1, 4, 0
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OFFSET
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1,1
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COMMENTS
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a(490) = a(491) = 0 and so the value of a(1306) is perhaps controversial. I have used the combinatorial definition 0^0 = 1 in my PARI script below. - Charles R Greathouse IV, Feb 15 2024
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LINKS
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EXAMPLE
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a(3)=a(1)^a(2), a(4)=first digit of a(2)^a(3)=3^8=6561, a(5)=2nd digit of a(2)^a(3)=3^8=6561, a(6)=3rd digit of a(2)^a(3)=3^8=6561
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PROG
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(PARI) list(lim)=my(v=List([2, 3]), i=1); while(#v<lim, my(t=digits(v[i]^v[i++])); if(#t==0, listput(v, 0), for(i=1, #t, listput(~v, t[i])))); while(#v>lim, listpop(~v)); Vec(v) \\ Charles R Greathouse IV, Feb 15 2024
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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