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%I #7 Nov 05 2013 02:32:34
%S 7,19,61,193
%N Let R_{k}(m) = the digit reversal of m in base k (R_{k}(m) is written in base 10). a(n) is the smallest y such that there are exactly n bases {k} (k >= 2 and (x < y)) solutions of the equation: R_{k}(x) = y and R_{k}(y) = x.
%e a(2)=19 because there are two solutions: R_{3}(11) = 19 and R_{3}(19) = 11, R_{9}(11) = 19 and R_{9}(19) = 11.
%Y Cf. A004086, A030101-A030108, A056960-A056963, A037183, A091974.
%K more,nonn,base
%O 1,1
%A _Naohiro Nomoto_, Mar 18 2004
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