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A085421
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a(0)=2, a(1)=1, a(n+2)=floor[(e-1/e)*a(n+1)+a(n-2)].
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2
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2, 1, 4, 10, 27, 73, 198, 538, 1462, 3974, 10802, 29363, 79816, 216962, 589764, 1603144, 4357797, 11845720, 32200005, 87528688, 237927642, 646754385, 1758060692, 4778904432, 12990409077, 35311592938, 95986861417
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OFFSET
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0,1
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COMMENTS
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a(n+1)/a(n) converges to e.
For n>0, floor[log a(n)] = n-1.
This resembles a Lucas sequence.
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LINKS
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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