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A071865
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Smallest k such that the simple continued fraction for Sum(d|k, 1/d) contains exactly n elements.
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4
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1, 2, 4, 14, 22, 26, 75, 195, 330, 324, 935, 1598, 3422, 3663, 10191, 14066, 12099, 53661, 121555, 182169, 235509, 307615, 633945, 2097595, 2072198, 2643298, 6544282, 8675343, 13670722, 17573794, 85112326, 77295778, 235873898, 362150458, 544042486, 1457255474
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OFFSET
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1,2
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LINKS
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EXAMPLE
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sum(d|195, 1/d) = 112/65 and 112/65 continued fraction is [1, 1, 2, 1, 1, 1, 1, 3] which contains 8 elements. There is no smaller number than 195 with this property hence a(8)=195.
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MATHEMATICA
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a = Table[0, {50}]; Do[b = Length[ ContinuedFraction[ Apply[ Plus, 1/Divisors[n]]]]; If[ a[[b]] == 0, a[[b]] = n], {n, 1, 10^7}]
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PROG
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(PARI) for(n=1, 21, s=1; while(length(contfrac(sumdiv(s, d, 1/d)))<n, s++); print1(s, ", "))
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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