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A067818
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Start with 1. To get a(n+1), describe a(n) in terms of the number of 0's, 1's, 2's,...,9's it has. Do not ignore leading 0's in the computation, but ignore them when listing the terms.
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0
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1, 110203040506070809, 100211213141516171819, 201012213141516171819, 20913213141516171819, 10812223141516171829, 10714213141516172819, 10812213241516271819, 10714213141516172819, 10812213241516271819, 10714213141516172819, 10812213241516271819
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OFFSET
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1,2
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COMMENTS
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If leading 0's are not included in the computation, the sequence becomes constant after the third term.
Including leading 0's, the sequence oscillates between 10714213141516172819 and 10812213241516271819 from a(7) onward. - Sean A. Irvine, Jan 08 2024
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REFERENCES
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Pickover, C. "Wonders of Numbers", Oxford Univ. Press, 2001.
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LINKS
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C. A. Pickover, "Wonders of Numbers, Adventures in Mathematics, Mind and Meaning," Zentralblatt review
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EXAMPLE
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1 has 0 0's, 1 1's, 0 2's, 0 3's, 0 4's, 0 5's, 0 6's, 0 7's, 0 8's, 0 9's, so the term following 1 is 00110203040506070809. Ignore the two leading zeros when listing this term, but include them in the computation of the third term. The second term has 10 0's, 2 1's, 1 2's, 1 3's, 1 4's, 1 5's, 1 6's, 1 7's, 1 8's, 1 9's, so the third term is 100211213141516171819.
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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