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A067293
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Numbers k such that prime(k+1)-(k+1)*tau(k+1) = prime(k)-k*tau(k) where tau(k) = A000005(k) is the number of divisors of k.
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5
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2, 14, 38, 85, 93, 122, 135, 213, 243, 301, 387, 394, 537, 603, 694, 766, 778, 903, 963, 1041, 1083, 1265, 1346, 1354, 1382, 1401, 1412, 1706, 1713, 1729, 1882, 1981, 2077, 2126, 2306, 2540, 2644, 2685, 2697, 2702, 2854, 2874, 2986, 3068, 3081, 3117, 3310
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OFFSET
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1,1
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LINKS
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MATHEMATICA
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f[n_] := f[n] = Prime[n] - n * DivisorSigma[0, n]; Select[Range[3500], f[#] == f[#+1] &] (* Amiram Eldar, Apr 08 2024 *)
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PROG
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(PARI) f(n) = prime(n) - n * numdiv(n);
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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