|
|
A067003
|
|
Number of numbers <= n with same number of distinct prime factors as n.
|
|
10
|
|
|
1, 1, 2, 3, 4, 1, 5, 6, 7, 2, 8, 3, 9, 4, 5, 10, 11, 6, 12, 7, 8, 9, 13, 10, 14, 11, 15, 12, 16, 1, 17, 18, 13, 14, 15, 16, 19, 17, 18, 19, 20, 2, 21, 20, 21, 22, 22, 23, 23, 24, 25, 26, 24, 27, 28, 29, 30, 31, 25, 3, 26, 32, 33, 27, 34, 4, 28, 35, 36, 5, 29, 37, 30, 38, 39, 40, 41
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,3
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
a(11)=8 since 2,3,4,5,7,8,9,11 each have one distinct prime factor. a(12)=3 since 6,10,12 each have two distinct prime factors.
Column n lists the a(n) positive integers less than or equal to n with the same number of distinct prime factors as n:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
---------------------------------------------------------------------
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
2 3 4 5 7 8 6 9 10 11 12 14 13 16 15 17 18
2 3 4 5 7 8 6 9 10 12 11 13 14 16 15
2 3 4 5 7 8 6 10 9 11 12 13 14
2 3 4 5 7 6 8 9 10 11 12
2 3 4 5 7 8 6 9 10
2 3 4 5 7 8 6
2 3 4 5 7
2 3 4 5
2 3 4
2 3
2
(End)
|
|
MATHEMATICA
|
Table[Length[Select[Range[n], PrimeNu[#]==PrimeNu[n]&]], {n, 100}] (* Gus Wiseman, Dec 28 2018 *)
|
|
PROG
|
(PARI) a(n) = my(nb = #factor(n)~); sum(k=1, n, #factor(k)~ == nb); \\ Michel Marcus, Jul 13 2019
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|