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A060768 Pseudo-Kaprekar triples: q such that if q=x+y+z, then q^3=x*10^i + y*10^j + z, where (y*10^j+z < 10^i) and z < 10^j. 4

%I #4 Oct 09 2019 07:49:44

%S 1,8,10,45,100,134,297,783,972,1000,1368,1611,2322,2710,2728,3086,

%T 4445,4544,4949,5049,5455,5554,7172,10000,19908,21268,27100,44443,

%U 55556,60434,76581,77778,100000,103239,133334,143857,199728,208494,226071

%N Pseudo-Kaprekar triples: q such that if q=x+y+z, then q^3=x*10^i + y*10^j + z, where (y*10^j+z < 10^i) and z < 10^j.

%C True Kaprekar triples (A006887) must have j=n and i=2n, where n is the number of digits in q.

%H Giovanni Resta, <a href="/A060768/b060768.txt">Table of n, a(n) for n = 1..280</a>

%e 134^3=2406104 and 134=24+06+104. 134 is not a Kaprekar triple since the three terms of the sum would need to be 2, 406 and 104. 134 is not a term of A328198 because one addend (06) begins with '0'.

%Y Cf. A006887, A328198.

%K nonn,base

%O 1,2

%A Larry Reeves (larryr(AT)acm.org), Apr 24 2001

%E Offset changed to 1 by _Giovanni Resta_, Oct 09 2019

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