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A055273 a(n) = 3*a(n-1) - a(n-2) with a(0) = 1, a(1) = 8. 4
1, 8, 23, 61, 160, 419, 1097, 2872, 7519, 19685, 51536, 134923, 353233, 924776, 2421095, 6338509, 16594432, 43444787, 113739929, 297775000, 779585071, 2040980213, 5343355568, 13989086491, 36623903905, 95882625224, 251023971767, 657189290077, 1720543898464 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
REFERENCES
A. H. Beiler, Recreations in the Theory of Numbers, Dover, N.Y., 1964, pp. 194-196.
LINKS
Tanya Khovanova, Recursive Sequences
FORMULA
a(n) = (8*(((3 + sqrt(5))/2)^n - ((3 - sqrt(5))/2)^n) - (((3 + sqrt(5))/2)^(n - 1) - ((3 - sqrt(5))/2)^(n - 1)))/sqrt(5).
G.f.: (1 + 5*x)/(1 - 3*x + x^2).
From Rigoberto Florez, Dec 24 2018: (Start)
a(n) = Fibonacci(2n+2) + 5*Fibonacci(2n),
a(n) = 3*Fibonacci(2n+2) - Fibonacci(2n-3). (End)
E.g.f.: (1/5)*exp(3*x/2)*(5*cosh(sqrt(5)*x/2) + 13*sqrt(5)*sinh(sqrt(5)*x/2)). - Franck Maminirina Ramaharo, Dec 26 2018
a(n) = ChebyshevT(n, 3/2) + (13/2)*ChebyshevU(n-1, 3/2) = ChebyshevU(n, 3/2) + 5*ChebyshevU(n-1, 3/2). - G. C. Greubel, Jan 17 2020
MAPLE
seq(coeff(series((1+5*x)/(1-3*x+x^2), x, n+1), x, n), n = 0 .. 30); # Muniru A Asiru, Dec 29 2018
MATHEMATICA
Table[3Fibonacci[2n+2]-Fibonacci[2n-3], {n, 0, 20}] (* Rigoberto Florez, Dec 24 2018 *)
LinearRecurrence[{3, -1}, {1, 8}, 30] (* Vincenzo Librandi, Dec 25 2018 *)
PROG
(Magma) [Fibonacci(2*n+2) + 5*Fibonacci(2*n): n in [0..30]]; // Vincenzo Librandi, Dec 25 2018
(GAP) a:=[1, 8];; for n in [3..30] do a[n]:=3*a[n-1]-a[n-2]; od; Print(a); # Muniru A Asiru, Dec 29 2018
(PARI) vector(30, n, fibonacci(2*n) + 5*fibonacci(2*n-2) ) \\ G. C. Greubel, Jan 17 2020
(Sage) [fibonacci(2*n+2) +5*fibonacci(2*n) for n in (0..30)] # G. C. Greubel, Jan 17 2020
CROSSREFS
Sequence in context: A048467 A002765 A048770 * A296323 A241353 A362163
KEYWORD
easy,nonn
AUTHOR
Barry E. Williams, May 28 2000
STATUS
approved

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Last modified March 29 02:23 EDT 2024. Contains 371264 sequences. (Running on oeis4.)