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A051154
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a(n) = 1 + 2^k + 4^k where k = 3^n.
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8
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OFFSET
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0,1
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COMMENTS
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The first three terms are prime. Are there more? Golomb shows that k must be a power of 3 in order for 1 + 2^k + 4^k to be prime. - T. D. Noe, Jul 16 2008
The next term, a(5) has 147 digits and is too large to include in DATA. - David A. Corneth, Aug 19 2020
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LINKS
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FORMULA
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a(n) = (2^(3^(n+1))-1)/(2^(3^n)-1).
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MAPLE
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F:= proc(n, r) local p; p := ithprime(r); (2^(p^(n+1))-1)/(2^(p^n)-1); end:
[ seq(F(n, 2), n=0..5) ];
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MATHEMATICA
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Table[4^(3^n) + 2^(3^n) + 1, {n, 1, 5}] (* Artur Jasinski, Oct 31 2011 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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