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A038498
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Matrix inverse of partition triangle A008284.
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24
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1, -1, 1, 0, -1, 1, 1, -1, -1, 1, 0, 1, -1, -1, 1, 0, 1, 0, -1, -1, 1, -1, 1, 1, 0, -1, -1, 1, -1, 0, 2, 0, 0, -1, -1, 1, 0, -1, 0, 2, 0, 0, -1, -1, 1, 0, -2, 1, 1, 1, 0, 0, -1, -1, 1, 1, -2, -1, 1, 1, 1, 0, 0, -1, -1, 1, 1, -1, -2, 0, 2, 0, 1, 0, 0, -1, -1, 1
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OFFSET
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1,31
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COMMENTS
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Since A008284 has only ones in its first column, the sum of terms for any row n > 1 is 0. - François Marques, Feb 09 2021
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LINKS
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FORMULA
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EXAMPLE
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Triangle begins:
1;
-1,1;
0,-1,1;
1,-1,-1,1;
...
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PROG
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(PARI) tp(n, k) = if (n<1, 0, if (k<1, 0, if (k == n, 1, if (k > n, 0, tp(n-1, k-1) + tp(n-k, k)))));
tabl(nn) = {mtp = matrix(nn, nn, n, k, tp(n, k)); mtpi = mtp^(-1); for (n = 1, nn, for (k = 1, n, print1(mtpi[n, k], ", "); ); print(); ); } \\ Michel Marcus, Mar 04 2014
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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