%I #9 Mar 30 2012 18:55:51
%S 2,2,2,3,4,5,7,10,13,18,25,35,48,67,93,129,179,249,346,481,668,928,
%T 1290,1792,2491,3462,4811,6686,9292,12913,17946,24940,34660,48169,
%U 66942,93032,129291,179681,249711,347034,482289,670259,931489
%N a(n) = [ a(n-1)/a(1) + a(n-2)/a(2) + ... + a(1)/a(n-1) ], for n >= 3.
%F It seems that a(n) = floor(A*B^n) + 0 or + 1 where A=0.665223258777... and B=1.3897449962460091643408... - _Benoit Cloitre_, Oct 24 2003
%K nonn
%O 1,1
%A _Clark Kimberling_
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