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A020998
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Numbers n such that the sum of the digits of Lucas(n) in base 12 is n.
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1
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1, 7, 165, 227, 278, 322, 323, 385, 414, 433, 439, 634, 860, 964, 1045, 1268
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OFFSET
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1,2
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LINKS
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PROG
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(PARI) isok(n) = vecsum(digits(fibonacci(n+1)+fibonacci(n-1), 12)) == n; \\ Michel Marcus, Feb 18 2015
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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