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A016159 Expansion of 1/((1-4x)(1-12x)). 0

%I #19 Jul 15 2018 22:03:11

%S 1,16,208,2560,30976,372736,4476928,53739520,644939776,7739539456,

%T 92875522048,1114510458880,13374142283776,160489774514176,

%U 1925877562605568,23110531825008640,277326386195070976

%N Expansion of 1/((1-4x)(1-12x)).

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (16,-48).

%F a(n) = 2^(2*n-1)*(3^(n+1)-1). - _Bruno Berselli_, Feb 09 2011

%F a(n) = 12*a(n-1) + 4^n with a(0)=1. - _Vincenzo Librandi_, Feb 09 2011

%F a(n) = 16*a(n-1) - 48*a(n-2), a(0)=1, a(1)=16. - _Harvey P. Dale_, Nov 30 2011

%F a(n) = 2^(2n-3)*(3^n-1). - _Harvey P. Dale_, Nov 30 2011

%t Join[{a=1,b=16},Table[c=16*b-48*a;a=b;b=c,{n,40}]] (* _Vladimir Joseph Stephan Orlovsky_, Feb 08 2011 *)

%t CoefficientList[Series[1/((1-4x)(1-12x)),{x,0,20}],x] (* or *) LinearRecurrence[{16,-48},{1,16},20] (* _Harvey P. Dale_, Nov 30 2011 *)

%K nonn

%O 0,2

%A _N. J. A. Sloane_

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